45x^2+900x-180=0

Solution for 45x^2+900x-180=0 equation:

45x^2+900x-180=0

a = 45; b = 900; c = -180;
Δ = b2-4ac
Δ = 9002-4·45·(-180)
Δ = 842400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{842400}=\sqrt{32400*26}=\sqrt{32400}*\sqrt{26}=180\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(900)-180\sqrt{26}}{2*45}=\frac{-900-180\sqrt{26}}{90}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(900)+180\sqrt{26}}{2*45}=\frac{-900+180\sqrt{26}}{90}
$